Question

Find the product of (2x-y+3z)(4x square+y square +9z square+2xy+3yz-6xz)

Answer 1

Answer:

8x³-y³+27z³+18xyz

Step-by-step explanation:

=> (2x-y+3z)(4x² + y²+ 9z² + 2xy + 3yz - 6xz)

=  (2x-y+3z)( (2x)² + (y)² + (3z)² - (2x)(-y) - (-y)(3z) - (3z)(2x) )

=> Identity:- (a+b+c)(a²+b²+c²-ab-bc-ca) = a³+b³+c³-3abc

=> (2x-y+3z)( (2x)² + (y)² + (3z)² - (2x)(-y) - (-y)(3z) - (3z)(2x) )  

=   (2x)³+(-y)³+(3z)³-3(2x)(-y)(3z)  =  8x³-y³+27z³+18xyz