Math, asked by flame10, 1 year ago

find the product of (2x-y+3z)(4x²+y²+9z²+2xy+3yz-6xz)

Answers

Answered by arc555
48
(2x-y+3z)(4x²+y²+9z²+2xy+3yz-6xz)
(2x-y+3z)((2x)²+(y)²+(3z)²-(-y*2x)-(-y*3z)-(2x*3z)
(2x)³+(-y)³+(3z)³-(3×-y×2x×3z) [ ∵(a+b+c)(a²+b²+c²-ab-bc-ca)= a³+b³+c³-3abc]
8³-y³+27+³+18xyz Ans.
Answered by ishi310
9

Answer:

(2x)³ + (y)³ + (3z)³ = 3×(2x)×(y)×(3z) = 18xyz

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