Question

Find the product of 2x2 + 3y - 4 and 3x2 + 4y + 5using Urdhva
Tiryak Vidhi.​

Answer 1

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Q1) Find The product of 2x²+3y-4 and 3x²+4y+5

$\: \: \underline{ \boxed{ \bf { \ddot \smile \: answer}}}$

$\: \: \: \\ \hookrightarrow \tt{(2 {x}^{2} + 3y - 4)(3 {x}^{2} + 4y + 5)}$

$\: \: \: \\ \hookrightarrow \displaystyle \tt{2 {x}^{2} (3 {x}^{2} + 4y + 5) + 3y( {3x}^{2} + 4y + 5) - 4( {3x}^{2} + 4y + 5)}$

$\: \: \\ \hookrightarrow \displaystyle \tt{ {4x}^{4} + 8 {x}^{2} y + 10 {x}^{2} + 9 {x}^{2}y + 12 {y}^{2} + 15y - 12 {x}^{2} - 16y - 20}$

$\: \: \: \\ \hookrightarrow \displaystyle \tt{4 {x}^{4} + {8x}^{2} y + 9 {x}^{2} y + 10 {x}^{2} - 12 {x}^{2} + 12 {x}^{2} + 15y - 16y - 20}$

$\: \: \\ \hookrightarrow \displaystyle \tt{4 {x}^{4} + 17 {x}^{2} y + 10 {x}^{2} - y - 20 = 0}$

$\: \checkmark \boxed{ \displaystyle \bf \color{brown} \: {4x}^{4} + {17x}^{2} y + 10 {x}^{2} - y - 20 = 0}$