Question

find the product of 2x2 y2 , 3y2 Z and Z2 × 3 = b = 7cm​

Answer 1

Answer:

2️

Step-by-step explanation:

Answer 2

(i) 7x (ii) 5y − 7z (iii) 3x3 −5x2 −11 (iv) 1 −8a−7a 2−7a3

(v) 5m−3 (vi) a (vii) 4

(viii) 3y2−7y + 5

ANSWER:

It is known that, expressions with one term is called monomial, expressions with two terms are binomials, expressions with three terms are trinomials and expression with more than three terms are polynomials.

(i) 7x = Monomial

(ii) 5y−7z = Binomial

(iii) 3x3−5x2−11 = Trinomial

(iv) 1−8a−7a2−7a3 = Polynomial

(v) 5m−3 = Binomial

(vi) 4 = Monomial

(vii) 3y2−7y+5 = Trinomial

Page No 57:

Question 1:

Add.

(i) 9p + 16q ; 13p + 2q (ii) 2a + 6b + 8c; 16a + 13c+ 18b

(iii) 13x2−12y2 ; 6x2 − 8y2 (iv) 17a2 b2 + 16c ; 28c − 28a2 b2

(v) 3y2 − 10y + 16 ; 2y−7 (vi) −3y2 + 10y −16 ; 7y2 + 8

ANSWER:

(i) (9p + 16q) + (13p + 2q)

= 9p + 16q + 13p + 2q

=(9p + 13p) + (16q + 2q)

=22p + 18q

(ii) (2a + 6b + 8c) + (16a + 13c + 18b)

= 2a + 6b + 8c + 16a + 13c + 18b

= (2a + 16a) + (6b + 18b) + (8c + 13c)

= 18a + 24b + 21c

(iii) (13x2 − 12y2) + (6x2 − 8y2)

= 13x2 − 12y2 + 6x2 − 8y2

= (13x2 + 6x2) + (−12y2 − 8y2)

=19x2 + (−20y2)

=19x2 − 20y2

(iv) (17a2b2 + 16c) + (28c − 28a2b2)

= 17a2b2 + 16c + 28c − 28a2b2

= (17a2b2 − 28a2b2) + (16c + 28c)

= −11a2b2 + 44c

(v) (3y2 − 10y + 16) + (2y − 7)

= 3y2 − 10y + 16 + 2y − 7

= 3y2 + (−10y + 2y) + (16 − 7)

=3y2 + (−8y) + 9

=3y2 − 8y + 9

(vi) (−3y2 + 10y − 16) + (7y2 + 8)

= −3y2 + 10y − 16 + 7y2 + 8

= (−3y2 + 7y2) + 10y + (−16 + 8)

= 4y2 + 10y + (−8)

= 4y2 + 10y − 8