Question

find the product of 2x²-y²,3y²z and -z²x³​

Answer 1

Step-by-step explanation:

Given:2x²-y²,3y²z and -z²x³

To find:find the product.

Solution:

Tip:Powers will add when base are same during multiplication.

for eq: y²×y=y³

Step 1: Write last two expression and multiply

$(3 {y}^{2} z) \times ( - {z}^{2} {x}^{3} ) = - 3 {x}^{3} {z}^{3} {y}^{2}$

Step 2: Multiply the result of above step with first expression

$(2 {x}^{2} - {y}^{2} ) \times (- 3 {x}^{3} {z}^{3} {y}^{2}) = - 6{x}^{5} {z}^{3} {y}^{2} + 3 {x}^{3} {z}^{3} {y}^{4}$

Final answer:

Product of 2x²-y²,3y²z and -z²x³ is

$- 6{x}^{5} {z}^{3} {y}^{2} + 3 {x}^{3} {z}^{3} {y}^{4}$

Hope it helps you.

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