Question

find the product of 3/4a2(2/3b2+8ab)
​

Answer 1

Answer:

4a2

3

+3b2)4(

3b2

a2−2

)

=( \frac{3}{8a} + 6b) \: \times 2 \times \frac{2a - 2}{3b}=(

8a

3

+6b)×2×

3b

2a−2

= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 2}{3b}=

8a

3+48ab

×2×

3b

2a−2

= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 1}{3b}=

8a

3+48ab

×2×

3b

2a−1

= \frac{3 + 48ab}{4a} \times \frac{2(a - 1)}{3b}=

4a

3+48ab

×

3b

2(a−1)

= \frac{3(1 + 16ab)}{2a} \times \frac{a - 1}{3b}=

2a

3(1+16ab)

×

3b

a−1

= \frac{(1 + 16ab) \times (a - 1)}{2ab}=

2ab

(1+16ab)×(a−1)

= \frac{a - 1 + 16a {}^{2} b - 16ab}{2ab}=

2ab

a−1+16a

2

b−16ab

Answer 2

Answer:

after simplification it becomes =(1+12abb2)/2a2b2

Step-by-step explanation:

solution ..

=3/4a2(2/3b2+8ab)

=3/4a2[(2+24abb2)/3b2]

=(6+72abb2)/12a2b2

=6(1+12abb2)/12a2b2

=(1+12abb2)/2a2b2

Answers ..

hope it will help you