Question

find the product of (√3/5+√5/2) and (√5+√2)
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Answer 1

Answer:

Please mark as the brainliest.

Hope this helps you.

Step-by-step explanation:

$( \frac{ \sqrt{3} }{5} + \frac{ \sqrt{5} }{2} ) \times ( \sqrt{5} + \sqrt{2} )$

$= \frac{ \sqrt{3} \times \sqrt{5} }{5} + \frac{ \sqrt{3} \times \sqrt{2} }{5} + \frac{ \sqrt{5} \times \sqrt{5} }{2} + \frac{ \sqrt{5} \times \sqrt{2} }{2}$

$= \frac{ \sqrt{15} }{5} + \frac{ \sqrt{6} }{5} + \frac{5}{2} + \frac{ \sqrt{10} }{2}$

$= \frac{ \sqrt{15} + \sqrt{6} }{5} + \frac{5 + \sqrt{10} }{2}$

Answer 2

Hey there!

Here u go.....

The answer is

√3 +√5 + √30/5 + 5(√2)/2

Step-by-step explanation:

Given two irrational numbers

√3/5+√5/2 (√5+√2)

To find,

The product of the given two numbers

I want u to recall the Distributive property

a(b+c) = a×b+ a×c

(√3/5+√5/2) x (√5+√2)

Applying distributive property we get

=  √3/√5 (√5+√2) +√5/√2×(√5+√2)

Again applying distributive property we get

=  √3/√5 ×√5+ √3/√5  ×√2 +√5/√2×√5+√5/√2×√2

= √3 +√6/√5  + 5/√2 + √5

Now conjugate by multiplying the denominator to numerator and denominator

= √3 +√5 + √6/√5  × √5/√5 + 5/√2 ×√2/√2

√3 +√5 +  √30/5  + 5√2/2

Therefore the product of (√3/5+√5/2) and (√5+√2) = √3 +√5 + √30/5 + 5(√2)/2

Hope it helps!

Have a great day :)