Question

find the product of 3/5 and the reciprocal of - 9/.10

Answer 1

Step-by-step explanation:

the reciprocal of -9/0.10=0.10/9

3/5×0.10/9=0.2/3

0.2/3=2/10÷1/3

2/10×1/3=1/15

1/15=0.06666666...

Answer 2

Answer:

Step-by-step explanation:

Concept:

The concept of multiplication will be used to solve the question.

Given:

The two fractions which are mentioned in the question is $\frac{3}{5}$ and $-\frac{9}{10}$.

To Find:

First the reciprocal of $-\frac{9}{10}$  need  to be found out.And then we have to find out the product of  $\frac{3}{5}$ and the reciprocal of $-\frac{9}{10}$ .

Solution:

First we have to find out the reciprocal of $-\frac{9}{10}$.

The definition of a number's reciprocal in mathematics is that it is the equation that, when multiplied by the number, produces the result $1$. In other terms, two integers are considered to be reciprocals of one another when the product of those two numbers is $1$. The division of $1$ by a number is another way to describe its reciprocal.

The reciprocal of $-\frac{9}{10}$ is $-\frac{10}{9}$ .

Now the product of $\frac{3}{5}$ and $-\frac{10}{9}$ has to be found out.

The product will be $\frac{3}{5} \times (-\frac{10}{9} )=-\frac{2}{3}$.

Therefore, the final answer is $-\frac{2}{3}$ .

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