Question

Find the product of 3 root 2 and 3 root 4?

Answer 1

Question:- Product of 3√2 and 3√4

= 3√2 * 3√4

= 9√8

= 9 * 2√2

= 18√2

Method to Solve:

1) First Multiply the Numbers which are outside the Root.

2) Then Multiply The Numbers which are inside the root.

Here, 3 and 3 are multiplies and hence we got 9 and √2 and √4 are multiplied and we got √8

Further, By Prime Factorisation we simplified √8 as 2√2 and then we multiply 2 by 9 and thus we get the answer 18√2

Answer 2

Answer:-

Product of 3√2 and 3√4 is =>

$\mathsf{3 \sqrt{2} \times 3 \sqrt{4} }$

$\mathsf{ = 9 \sqrt{8} }$

$\mathsf{ = 9 \times 2 \sqrt{2}}$

$\mathsf{ = 18 \sqrt{2} }$