Question

find the product of (-3a²b+5abc) and (2a-3bc)​

Answer 1

Answer:

$\left(-3a^2b+5abc\right)\left(2a-3bc\right)$

  Using formula, $\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

                            $a=-3a^2b,\:b=5abc,\:c=2a,\:d=-3bc$

$-3\cdot \:2a^3b+3\cdot \:3a^2b^2c+5\cdot \:2a^2bc-5\cdot \:3ab^2c^2$

$-6a^3b+9a^2b^2c+10a^2bc-15ab^2c^2$