Question

find the product of (3p+2q)(2p-5q)

Answer 1

Answer:

6p^2-11pq-10q^2

Step-by-step explanation:

$(3p + 2q)(2p - 5q) \\ = 3p(2p - 5q) + 2q(2p - 5q) \\ = 3p(2p) + 3p( - 5q) + 2q(2p) + 2q( - 5q) \\ = 6 {p}^{2} - 15pq + 4pq - 10 {q}^{2} \\ = 6 {p}^{2} - 11pq - 10 {q}^{2}$

therefore,the product of (3p+2q)(2p-5q)=6p^2-11pq-10q^2

Answer 2

Solution:

( 3p + 2q ) ( 2p - 5q )

➝ 3p ( 2p - 5q ) 2q ( 2p - 5q )

First multiple 3p with second term 3 × 2 = 6 and we know p × p = p² combined 6p²

Now again multiply 3p with 5q first multiply coefficients as 3 × 5 = 15 and p × q = pq combined 15pq

Now let's take 2q .

first multiply 2q with 2p multiply coefficients first 2 × 2 = 4 and p × q = pq combined 4pq

Now multiply it with 5q coefficients first 2 × 5 = 10 and now variables q × q = q² combined 10q²

➝ 6p² - 15pq + 4qp - 10q²

➝ 6p² - 11pq - 10q²

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