Question

Find the product of (3p+q) and (p^2 q -2pq) and verify the result by taking p = 1 and q = 2.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

-10

Step-by-step explanation:

Multiply the first term of first algebric expression(i.e 3p) with the second algebric expression we get

3p*(p^2q-2pq)

=3p*p^2q+3p*(-2pq)

=3p^3q-6p^2q

now multiply the second term (i.e q) with the second algebric expression(i.e p^2q-2pq) we get

q*(p^2q-2pq)

=q*p^2q+q*(-2pq)

=q^2p-2pq^2

Now add both the equation we get

3p^3q-6p^2q+q^2p-2pq^2

now put p=1 and q=2 in above equation we get

3*1^3*2-6*1^2*2+2^2*1-2*1*2^2

=3*1*2-6*1*2+4*1-2*1*4

=6-12+4-8

=6+4-12-8

=10-20

=-10 Ans