Math, asked by anshika8767, 4 hours ago

find the product of

(3x-2y)^3 by using identity.​

Answers

Answered by jananivellaiyappan
1

(3x - 2y)³ = (3x)³ - (2y)³ - 3×3 x 3xx

2y (3x-2y)

3ab(a - b)]]

[.'[(a−b)³ = a³ - b³ -

= 27x³-8y³ - 18xy(3x-2y)

= 27x³-8y³ - 54x²y + 36xy² =

Answered by khushigarg09
1

Step-by-step explanation:

Apply the formula of (a-b) ^3

a^3+b^3-3a^2b-3ab^2

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