Find the product of (3x+2y)(3x-2y)(9x^2+4y^2) for what value of k(x+1) is a factor of p(x)=kx^2-x-4
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(3x+2y)(3x-2y)(9x^2+4y^2)
(9x^2-4y^2)(9x^2+4y^2)
81x^4-16y^4
P(-1)=k+2-4 =0
K=2
(9x^2-4y^2)(9x^2+4y^2)
81x^4-16y^4
P(-1)=k+2-4 =0
K=2
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Answer:
3x+2y)(3x-2y)(9x^2+4y^2)
(9x^2-4y^2)(9x^2+4y^2)
81x^4-16y^4
P(-1)=k+2-4 =0
K=2
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