Question

find the product of (3x-4) (3x+4)​

Answer 1

(a-b)(a+b) = a^2 - b^2

(3x-4)(3x+4) = (3x)^2 - 4^2

= 9x^2 - 16

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Answer 2

$\huge\underline\mathfrak{Solution}$

$(3x - 4)(3x + 4) \\ it \: is \: in \: for m\: of \: \\(a + b)(a - b) = {a}^{2} - {b}^{2}$

$a = 3x \\ b = 4$

$(3x - 4)(3x + 4) \\ {(3x)}^{2} - {(4)}^{2} \\ 9 {x}^{2} - 16$