Find the product of (3x-5y+4) (9x^2+25y^2+15xy-20y+12x+16)
Answers
Given : (3x-5y-4) (9x^2+25y^2+15xy-20y+12x+16) ( correction in question )
To find : Product
Solution:
Using identity :
a³ + b³ + c³ - 3abc = (a + b + c) (a² + b² + c² -ab - bc - ca)
(3x-5y-4) (9x²+25y²+15xy-20y+12x+16)
=(3x +(-5y) +4) ((3x)²+(-5y)² -(3x * (-5y)) - ((-4) * (-5y)) -(3x * (-4)) +(-4)²)
=(3x +(-5y) +4) ((3x)²+(-5y)²+ (-4)² -(3x * (-5y)) - ((-5y) *(-4)) - (3x * (-4)) )
a = 3x
b = - 5y
c = - 4
(3x)³ + (-5y)³ +(-4)³ - 3(3x)(-5y)(-4)
= 27x³ - 125y³ - 64 - 180xy
(3x-5y-4) (9x²+25y²+15xy-20y+12x+16) = 27x³ - 125y³ - 64 - 180xy
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