Question

find the product of (3x²+9) (6y²-7)​

Answer 1

Answer:

$Ans:-12x^{2}y^{2} -21x^{2} + 54y^{2} -63$

Step-by-step explanation:

  $(3x^{2}+9)(6y^{2}-7)$

= $3x^{2}.6y^{2} + 3x^{2}.(-7) + 9.6y^{2}+9.(-7)$

= $12x^{2}y^{2} -21x^{2} + 54y^{2} -63$

$Ans:-12x^{2}y^{2} -21x^{2} + 54y^{2} -63$

Answer 2

Answer:

18x^2y^2 - 21x^2 + 54y^2 - 63

Step-by-step explanation:

(3x^2 + 9) (6y^2 - 7)

3x^2(6y^2 - 7) + 9(6y^2 - 7)

=18x^2y^2 - 21x^2 + 54y^2 - 63