Question

Find the product of 3x²y, 4xy² and 7x³y³​

Answer 1

Answer:

81x^6y^6

Step-by-step explanation:

3x^2y × 4xy^2 × 7x^3y³^3

= 3 × x^2 × y × 4 × x × y^2 × 7 × x^3 × y^3

= 3 × 4 × 7 × x^3 × x^2 × x × y^3 × y × y^2

= 81 × x^( 3 + 2 + 1 ) × y^( 3 + 1 + 2 )

= 81 × x^6 × y^6

= 81x^6y^6

Answer 2

3x²y × 4xy² × 7x³y³

=> (3×4×7) × ${(x)}^{(2+1+3)} × {(y)}^{(1+2+3)}$

=> 84 x⁶ y⁶

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