Question

find the product of 3x³ y² and (2x - 3y). Also verify the result for x=2 and y=-1​

Answer 1

Answer:

3x  

3

y  

2

×(2x−3y)

=3x  

3

y  

2

⋅2x−3x  

3

y  

2

⋅3y

=6x  

4

y  

2

−9x  

3

y  

3

 

Now, for x=−1,y=2, we have

L.H.S.-

3x  

3

y  

2

×(2x−3y)

=3(−1)  

3

(2)  

2

(2⋅(−1)−3⋅(2))

=3⋅(−1)⋅4×(−2−6)

=(−12)×(−8)

=96

R.H.S.-

6x  

4

y  

2

−9x  

3

y  

3

 

=6(−1)  

4

(2)  

2

−9(−1)  

3

(2)  

3

 

=6⋅1⋅4−9⋅(−1)⋅8

=24+72

=96

∵ L.H.S. = R.H.S.

Hence verified.

Step-by-step explanation: