find the product of 3x³y² and (2x-3y)and also verify for x=2,y=-1
Answers
Answered by
3
Answer:
I think it is 3x³y²2x-3y
Step-by-step explanation:
if x=2,y=1
3x³y³2x-y=
3³(2³)[1³][{2(2)}-1]=
9(8)(1)[4-1]=
72(3)=
216
I THINK THIS IS ANSWER
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Answered by
0
Answer:
x=2 and y=-1
(3x²y²)(2x-3y)
(3×2²×-1²)(2×2-3×-1)
(3×4×1)(4×3)
12×12=144
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