find the product of 3xy and 2/7 x^2y
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Step-by-step explanation:
Multiplying term by term and then adding,
(2x2−3xy+y2)×(2y2−xy−x2)
=2x2(2y2−xy−x2)−3xy(2y2−xy−x2)+y2(2y2−xy−x2)
=4x2y2−2x3y−2x4−6xy3+3x2y2+3x3y+2y4−xy3−x2y2
=6x2y2−x3y−7xy3+2y4−2x4
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Answer:
3xy × 2/7 x×x×y
=6/7x^3y^2
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