find the product of 3xy2, -3xy3, xy2?
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+3xy2-3xy3+xy2
+3xy2 and +xy2 are positive numbers
-3xy3 is negative number
+×+=+
= +3xy2+ +xy2= 34113
=34113-3xy3= ur solution
Answered by
0
Answer:
-9x^3y^7
Step-by-step explanation:
3xy2×{-3xy^3}xy2
add power of variables and multiply the coefficients.
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