Find the product of (-3xyz) (-4/9x^2z) (-27/2xy^2z) and verify the result for x=2,y=3,z=-1.
Please explain step by step and verify with the process of L.H.S. or R.H.S.
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Step-by-step explanation:
We have,−3xyz(49x2z)(−272xy2z)=(−43x3yz)(−272xy2z)=18x4y3z2
Now, for x=2, y=3 and z=−118(2) 4(3) 3 (−1)2=18×16×27×1 = 7776
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