Question

find the product of (-3xyz)(4/9x2z)(-27/2xy2z)and verify the result for x=2,y=3,z=1​

Answer 1

Answer:

the product of (-3xyz)(4/9x2z)(-27/2xy2z) is 18$x^{4}$$y^{3}$$z^{3}$

Step-by-step explanation:

The product of ( -$\frac{-3}{1}$×$\frac{4}{9}$×$\frac{-27}{2}$)(x×$x^{2}$×x)(y×$y^{2}$)(z×z×z)

=   ($\frac{-1}{1}$×$\frac{2}{3}$×$\frac{-27}{1}$)($x^{4}$×$y^{3}$×$z^{3}$)

 =(-54/3)($x^{4}$×$y^{3}$×$z^{3}$)=-18$x^{4}$×$y^{3}$×$z^{3}$

                                 = 18$x^{4}$$y^{3}$$z^{3}$

the product of (-3xyz)(4/9x2z)(-27/2xy2z) is 18$x^{4}$$y^{3}$$z^{3}$