find the product of 3y[4y+7] [4y-7]
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Answer: 48y^3 - 147y
Step-by-step explanation:
3y(4y+7)(4y-7)
= 3y [(4y)^2 - 7^2]
= 3y (16y^2-49)
= 48y^3 - 147y
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