Question

find the product of 4/3 mn, -5/12 m^2n^2 and -3/5 m^3n^3​

Answer 1

Answer:

y=mn^2

PREMISES

S=mn, m^2n^3, m^3n^5,…

This partial sequence suggests a pattern from left to right where the terms increase by a factor or common ratio of mn^2.

y=the common ratio of the sequence mn, m^2n^3, m^3n^5,…

CALCULATIONS

The common ratio or multiple of the partial sequence mn, m^2n^3, m^3n^5… can be denoted by the statement:

y=m^2n3/mn

y=m^(2–1)n^(3–1)

y=mn^2

ALGORITHM

a(n)=(n-1)mn^2, where n=any nth term in the sequence, n-1=the previous term, and where mn^2=the common ratio, factor, or multiple.

PATTERN

(0) 1/n

(1) 1/n(mn^2)=mn

(2) mn(mn^2)=m^2n^3

(3) m^2n^3(mn^2)=m^3n^5

(4) m^3n^5(mn^2)=m^4n^7

(5) m^4n^7(mn^2)=m^5n^9

(6) m^5n^9(mn^2)=m^6n^11

(7) m^6n^11(mn^2)=m^7n^13

(8) m^7n^13(mn^2)=m^8n^15

(9) m^8n^15(mn^2)=m^9n^17

(10) m^9n^17(mn^2)=m^10n^19

(100) m^99n^197(mn^2)=m^100n^199

and so forth

C.H.