Math, asked by Nushrat109, 9 months ago

find the product of (4m^2n^2) (3m^2n+7mn+9mn^2 - 15)​

Answers

Answered by rajeevr06
9

Answer:

4 {m}^{2}  {n}^{2} (3 {m}^{2} n + 7mn + 9m {n}^{2}  - 15) = 12 {m}^{4}  {n}^{3}  + 28 {m}^{3}  {n}^{3} +  36 {m}^{3}  {n}^{4}  - 60 {m}^{2}  {n}^{2}

Answered by bhakti75
1

Answer:

4m 2n 2

(3m

2

n+7mn+9mn

2

−15)=12m

4

n

3

+28m

3

n

3

+36m

3

n

4

−60m

2 n2

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