Find the product of (4x-3y) and (16x^2+12xy+9y^2) using suitable identity
Answers
Answered by
6
( 4x -3y) and ( 16x² +12xy + 9y²) are given
(4x -3y){(4x)² +(4x)(3y)+(3y)²} =?
we know,
( a - b)( a² + ab + b²) = a³ -b³
use this identity for solving this
so,
(4x -3y){(4x)² +(4x)(3y)+(3y)² } =(4x)³ -(3y)³
=64x³ -27y³
(4x -3y){(4x)² +(4x)(3y)+(3y)²} =?
we know,
( a - b)( a² + ab + b²) = a³ -b³
use this identity for solving this
so,
(4x -3y){(4x)² +(4x)(3y)+(3y)² } =(4x)³ -(3y)³
=64x³ -27y³
Answered by
6
Hi friend,
first solve 16x^2+12xy+9y^2
(4x)^2+(4x)(3y)+(3y)^2
(4x-3y){((4x)^2+(4x)(3y)+(3y)^2)}
It is in the form (a-b)(a^2+ab+b^2)=a^3-b^3
in this way we can write (4x)^3-(3y)^3=64x^3-27y^3
first solve 16x^2+12xy+9y^2
(4x)^2+(4x)(3y)+(3y)^2
(4x-3y){((4x)^2+(4x)(3y)+(3y)^2)}
It is in the form (a-b)(a^2+ab+b^2)=a^3-b^3
in this way we can write (4x)^3-(3y)^3=64x^3-27y^3
mysticd:
Last line is wrong plz edit
Similar questions