Math, asked by toneygillian, 3 months ago

Find the product of (4z2 + 7z – 8) and (–z + 3).

The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 +(A.)z2+ (B.)z – 24.

Answers

Answered by ks479

4

Answer:

-4z^3 + 5z^2 + 29z - 24

Step-by-step explanation:

(4z^2 + 7z - 8) (-z+3)

-4z^3 +12z^2 -7z^2 +21z +8z -24

-4z^3 + 5z^2 +29z -24

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