Math, asked by ritikgupta7732, 6 months ago

Find the product of (64a²-56ab+49b²)(8a+7b) *

Answers

Answered by kavinsiddhu758
1

Answer:

\left(64a^2-56ab+49b^2\right)\left(8a+7b\right)\\= 64a^2\cdot \:8a+64a^2\cdot \:7b+\left(-56ab\right)\cdot \:8a+\left(-56ab\right)\cdot \:7b+49b^2\cdot \:8a+49b^2\cdot \:7b\\= 64\cdot \:8a^2a+64\cdot \:7a^2b-56\cdot \:8aab-56\cdot \:7abb+49\cdot \:8ab^2+49\cdot \:7b^2b\\= 512a^3+343b^3\\OR\\(8a^{3})+(7b^{3})

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