Question

Find the product of 6x^2y^2 and 5xyz and verify the product if x=1,y=2 and z=3​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$6 {x}^{2} {y}^{2} \times 5xyz \\ = (6 \times 5)( {x}^{2} \times x)( {y}^{2} \times y)(z) \\ = \underline {\underline{ 30 {x}^{3} {y}^{3} z}} \\ \\ \large{ \underline{ \underline{When \: \: \: x = 1, \: \: \: y = 2, \: \: \: z = 3}}} \\ 6 {x}^{2} {y}^{2} \times 5xyz \\ = (6 {(1)}^{2}{(2)}^{2} ) \times (5(1)(2)(3)) \\ = (6 \times 1 \times 4) \times (5 \times 2 \times 3) \\ = 24 \times 30 \\ = \underline {\underline{ 720}} \\ \\ \large{ \underline{ \underline{Answer \: \: Verification}} :} \\ 6 {x}^{2} {y}^{2} \times 5xyz \\ = 30 {x}^{3} {y}^{3} z \\ = 30 {(1)}^{3} {(2)}^{3} (3) \\ = 30 \times 1 \times 8 \times 3 \\ = \underline {\underline{720}} \\ \\ \large{ Answer \: \: Verified}$