Find the product of (6x - 3) and ( 2x² + x -4 )
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Answer:
2x³ - 11x² + 17x - 6 = 0
for x = 2 ; value of the equation is zero
(x - 2)(2x² - 7x + 3) = 0
(x - 2)(2x² - 6x - x +3) = 0
(x - 2){2x(x - 3) -1(x - 3)} = 0
(x - 2)(2x - 1)(x - 3) = 0
x = 2,1/2,3
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