Question

find the product of (7-3x)(7+3x)​

Answer 1

Answer:

49-$9x^{2}$

Step-by-step explanation:

By a^2-b^2, we get,

=(7-3x)(7+3x)

=(7)^2-(3x)^2

=49-9x^2

Answer 2

Answer :

$\large \implies \sf 49 - 9x^2$

Solution :

Method 1 :-

Simplifying

$\large \sf (7-3x) (7+3x) \\ \\ \implies\sf 7(7+3x) -3x(7+3x) \\ \\ \large \implies \sf 49 +\cancel{21x} \:\:\: \cancel{-21x} - 9x^2 \\ \\ \large \implies \sf 49 - 9x^2$

Method 2 :-

Using identify : (a+b)(a-b) = a²-b²

$\large \sf (7-3x) (7+3x) \\ \\ \large\implies \sf 7^2 - (3x)^2 \\ \\ \large \implies \sf 49 - 9x^2$

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