Question

find the product of -7a2b2 and -6ba2.answer this question​

Answer 1

Question :-

$\bf \:Find \: the \: product \: of \: - 7 {a}^{2} {b}^{2} \: and \: - 6b {a}^{2}$

Answer

Given :-

• Two algebraic expressions -7a²b² and (- 6ba²)

To find :

• Product of algebraic expression

Identity used :-

$\bf \: {a}^{m} \times {a}^{n} = {a}^{m + n}$

Solution :-

$\bf \:- (7 {a}^{2} {b}^{2}) \times (- 6b {a}^{2} )$

$\bf\implies \:( - 7) \times ( - 6) \times ( {a}^{2} \times {a}^{2} ) \times ( {b}^{2} \times b)$

$\bf\implies \:42( {a}^{ 2+ 2} )( {b}^{2 + 1} )$

$\bf\implies \:42 {a}^{4} {b}^{3}$

Answer 2

Answer:

Answer

Given :-

Two algebraic expressions -7a²b² and (- 6ba²)

To find :

Product of algebraic expression

Identity used :-

\bf \: {a}^{m} \times {a}^{n} = {a}^{m + n} a

m

×a

n

=a

m+n

Solution :-

\bf \:- (7 {a}^{2} {b}^{2}) \times (- 6b {a}^{2} )−(7a

2

b

2

)×(−6ba

2

)

\bf\implies \:( - 7) \times ( - 6) \times ( {a}^{2} \times {a}^{2} ) \times ( {b}^{2} \times b)⟹(−7)×(−6)×(a

2

×a

2

)×(b

2

×b)

\bf\implies \:42( {a}^{ 2+ 2} )( {b}^{2 + 1} )⟹42(a

2+2

)(b

2+1

)

\bf\implies \:42 {a}^{4} {b}^{3} ⟹42a

4

b

3