Question

find the product of -7xyz,3x^2y and -2xz check the results for x=1,y=2,z=3.​

Answer 1

Answer:

-7(1)(2)(3)=-42

3(1)^2 (2)=3^2 ×2=9×2=18

-2(1)(3)=-6

hope it is helpful

Answer 2

we have to find the product of -7xyz, 3x²y and -2xz and then we have to check the results for x =1 , y = 2 and z = 3

step 1 : multiplying all the given terms

i.e., product = (-7xyz) × (3x²y) × (-2xz)

= (-7 )(3)(-2) (xyz)(x²y)(xz)

= (42) (x¹ × x² × x¹)(y¹ × y¹)(z¹ × z¹)

= (42){x^(1 + 2 + 1)}{y^(1+1)} {z^(1 + 1)}

= (42)(x⁴)(y²)(z²)

= 42x⁴y²z²

hence, product of given terms = 42x⁴y²z²

step 2 : putting x = 1, y =2 and z = 3 in each of the three terms and product of given terms .

-7xyz = -7 × 1 × 2 × 3 = -42

3x²y = 3 × (1)² × 2 = 6

-2xz = -2 × 1 × 3 = -6

so, product of -7xyz, 3x²y and -2xz = -42 × 6 × -6 = -42 × -36 = 1152

and 42x⁴y²z² = 42(1)⁴(2)²(3)² = 42 × 36 = 1152

hence verified