Math, asked by mariyamkhan, 1 year ago

find the product of

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Answered by Shardul27
3
 \: \: \: (3 {a}^{2}b - 2b + 3c)(12 {a}^{2} b + 3c - 2d) \\ = (3 {a}^{2}b + 3c - 2b)(12 {a}^{2} b + 3c - 2d) \\ = 36 {a}^{2}b + 9 {a}^{2}bc - 6 {a}^{2}bd + 36 {a}^{2}bc + 9 {c}^{2} \\ \: \: \: \: \:- 6cd- 24 {a}^{2} {b}^{2} - 6bc + 4bd.

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mizanzafar2016: Wrong
mizanzafar2016: One step missing
Answered by mizanzafar2016
0

Answer:

Step-by-step explanation:

36a⁴b²+45a²bc-12bc+4b²+9c²

For previous steps see the other answer on this question which is given by Shardul27, scroll up.

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