Question

find the product of (a^2-2a+1)
(a^2+5a+6​

Answer 1

Answer:

Soln: Brother, if A and a in your problem, both are same, then we can factorise easily, that is (may be it is small 'a' only)

a²-5a+6 = 0 [ '0′ is b/z, the every quadratic eqns contains 0)

a²-6a+a+6 = 0 [b/z, by splitting 6 into 6×1 as it should give a constant by adding or subtracting them both]

Now, take the common terms out by grouping the terms into two which we can get two common terms. So, we get

a(a-6)-1(a-6) = 0

(a-6)(a-1) = 0

Now, we know that principle that, “if a.b = 0, then a = 0 or b = 0.” Therefore, from this we can write it as,

(a-6) = 0 or (a-1) = 0

a = 0+6 or a = 0+1

Therefore, a = 6 or a = 1 as, a quadratic eqn has two roots.

So, this is the method of factorisation for your problem. Thank you.