Question

Find the product of (a^2 bc^2) (9ab^2c^2)(-4ab^2c^4) and verify the result for a =1/2, b=-1,c=1​

Answer 1

Answer:

product of (a^2 bc^2)=-2.25

Step-by-step explanation:

Find the product of (a^2 bc^2)

(9ab^2c^2)(-4ab^2c^4) and verify the

result for a =1/2, b=-1,c=1​

Since:

a=1/2, b=-1,c=1

$(a^2 bc^2) (9ab^2c^2)(-4ab^2c^4)=(\frac{1}{2}^2* -1^2)(9*\frac{1}{2}*-1^2*1^2)(-4*\frac{1}{2}*-1^2*1^4)$

$(\frac{1}{2}^2* -1^2)(9*\frac{1}{2}*-1^2*1^2)(-4*\frac{1}{2}*-1^2*1^4)$

$(\frac{1}{4}*1)=\frac{1}{4}$

$(9*\frac{1}{2}*-1^2*1^2)=-4.5$

$(-4*\frac{1}{2}*-1^2*1^4)=2$

$\frac{1}{4}*-4.5*2=-2.25$