find the product of (a+b+c) and (-a+b-c) and add it to the product of (2a+b-c) and (a-2b+3c)
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Step-by-step explanation:
=[(a+b+c)×(-a+b-c)]+[(2a+b-c)×(a-2b+3c)
=[-a^2+ab-ac-ab+b^2-bc-ac+bc-c^2]+[2a^2-4ab+6ac+ab-2b^2+3bc-ac+2bc-3c^2]
= -a^2+b^2-c^2+2a^2-3ab+5ac-2b^2+5bc-3c^2
= a^2-b^2-4c^2-3ab+5ac+5bc
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