Find the product of (a + b + c - d ) ( a - b - c - d )
Answers
Answered by
2
Answer:
let us assume a,b,c, d are natural numbers and more than zero.
d = 1 , c = 1 gives b = 2 , a = (10! - 18 ) / 2,
a+b+c+d = 18, 14, 391
a = 3, b = 1 c = 1 gives d = (10! - 14 ) / 7
a+b+c+d = 5, 18, 403
the value of a+b+c+d lies in between the above two values.
if a,b,c, d can be 0 , then
values lie between 10 / 2 and 10/ 7
Answered by
1
Answer:
Follow simple product rule.
a^2-ab-ac-ad+ab-b^2-bc-bd+ac-bc-c^2-cd-ad+bd+cd+d^2
=a^2-b^2-c^2+d^2-2ad-2bc
Similar questions