Question

Find the product of

a) (y – 8) and (3y – 4)
b) (x – y) and (3x + 5y)

Answer 1

(y-8)×(3y-4)

y(3y-4)-8(3y-4)

3y²-4y-24y+32

3y²-28y+32

MARK IT AS BRAINLIEST

Answer 2

Answer:

a) $(y - 8)(3y - 4)$ $= 3y^2 - 28y + 32$

b) $(x - y)(3x + 5y)$ $=3x^2 + 2xy - 5y^2$

Step-by-step explanation:

a) $(y - 8)(3y - 4)$

$= y(3y - 4) - 8(3y - 4)$

$= 3y^2 - 4y - 24y + 32$

$= 3y^2 - 28y + 32$

b) $(x - y)(3x + 5y)$

$=x(3x + 5y) - y(3x + 5y)$

$=3x^2 + 5xy - 3xy - 5y^2$

$=3x^2 + 2xy - 5y^2$