Question

Find the product of : (-a²b),(abc)​

Answer 1

Answer:

-a³b²c is the answer

Step-by-step explanation:

(-a²b),(abc)​

(-a²b) x (abc)​

= -a³b²c

Answer 2

$\huge\color{blue}{\underline{\underline{answer\::}}}$

(-a²b) (abc)

Multiplying each digit of first bracket with second one seperately we get;

-a² (abc) + b²( abc)

-a³- a²b- a²c + b²a + b³ + b²c -------(1)

So , this is the required answer...

$\huge\color{yellow}{\underline{\underline{proof\::}}}$

From 1 ,

Taking -a² and +b² common respectively , we get

-a² (abc) + b²(abc)

(-a² b) + (abc)

Hence , proved.

Hope it helps :)