Question

find the product of

(ab²)(a+b²+c³)​

Answer 1

Answer:

refer to the attachment

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given :-

✭ a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

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To Prove :-

◈ The Above statement is true

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Proof :-

Before Solving we should know the formula,

a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)

Solving LHS

➝ a³ + b³ + c³ - 3abc

➝ (a³ + b³ ) + c³ - 3abc

➝ (a + b)³ - 3ab(a + b) +c³ - 3abc

➝ (a + b)³ - 3a²b - 3ab² + c³ - 3abc

➝ [(a + b)³ + c³] -3a²b - 3ab² - 3abc

➝ (a + b + c)³ - 3c(a + b)(a + b + c ) -3ab(a + b+ c)

➝ (a + b + c)[(a + b + c)² -3c(a +b) - 3ab]

➝ (a + b + c)[a² + b² + c² +2ab +2bc+ 2ca -3ca - 3bc - 3ab]

➝ (a + b + c)(a² + b² + c² - ab - bc -ca)

LHS = RHS

$\sf Hence \ Proved !!Hence Proved!!$

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