Math, asked by 09082008, 6 days ago

find the product of additive inverse and multiplicative inverse of -7/13 * 9/49

Answers

Answered by avipanwar646
1

Answer:

The product is -1.

Step-by-step explanation:

A number gives 0 ( additive identity ) after adding with its Additive inverse and it gives 1 ( multiplicative inverse ) after multiplication with its multiplicative inverse.

Here, the given number is,

-\frac{3}{7}−73

Let, x be the additive inverse of the number,

-\frac{3}{7}+x=0−73+x=0

x=\frac{3}{7}x=73

Thus, the additive inverse of -3/7 is 3/7.

Now, let the y be the multiplicative inverse of -3/7,

\implies \frac{-3}{7}\times y = 1\times y = -\frac{7}{3}⟹7−3×y=1×y=−37

Thus, the multiplicative inverse of -3/7 is -7/3.

Hence, the product of additive inverse and multiplicative inverse of minus 3 upon 7

=\frac{3}{7}\times \frac{-7}{3}=73×3−7

=-1=−1

Answered by vinishajha69
1

Step-by-step explanation:

the answer is -91/9....hope it is helpful for you

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