Find the product of all integers from –1 to -5.
Answers
Answer:
heya mate there's your answer
(-1)(-2)(-3)(-4)(-5)
(2)(12)(-5) (- × - = +)
(24)(-5)
(-120)
hope it helps you
Thank you
Answer:
Given a number, the task is to find the product of the digits of a number.
Examples:
Input: n = 4513
Output: 60
Input: n = 5249
Output: 360
Recommended: Please try your approach on {IDE} first, before moving on to the solution.
General Algorithm for product of digits in a given number:
Get the number
Declare a variable to store the product and set it to 1
Repeat the next two steps till the number is not 0
Get the rightmost digit of the number with help of remainder ‘%’ operator by dividing it with 10 and multiply it with product.
Divide the number by 10 with help of ‘/’ operator
Print or return the product
Below is the solution to get the product of the digits:
// cpp program to compute
// product of digits in the number.
#include<bits/stdc++.h>
using namespace std;
/* Function to get product of digits */
int getProduct(int n)
{
int product = 1;
while (n != 0)
{
product = product * (n % 10);
n = n / 10;
}
return product;
}
// Driver program
int main()
{
int n = 4513;
cout << (getProduct(n));
}
// This code is contributed by
// Surendra_Gangwar