Question

find the product of all the numbers from 0 to 100

Answer 1

Answer:

The product of all integers from 1 to 100 is 100!.

The number of trailing zeros in 100! is (100/5)+(100/25) = 24

The formula actually counts the number of factors 5 in n!, but since there are at least as many factors 2, this is equivalent to the number of factors 10, each of which gives one more trailing zero.

Answer 2

Answer:

0

Step-by-step explanation:

Any number multiplied by 0 gives 0. Example: n*0 =0

Given: Product of numbers from 0 to 100.

Therefore: Solution =

0*1*2*3*4*5*6*7*8*9*.....*99*100=0

As n*0=0

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