find the product of binomial(m^2-5) (6-mn^2)
Answers
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered}
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2 n−m
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2 n−m 3
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2 n−m 3 n
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2 n−m 3 n 3
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2 n−m 3 n 3 −30+5mn
To multiply a binomial, four multiplications must take place. The first two terms need to be multiplied by the other two terms as follows (the order of multiplication is not important as long as the correct terms are being multiplied):\begin{gathered}(m^{2}n-5)(6-mn^{2})\\=6m^2n-m^3n^3-30+5mn^2\end{gathered} (m 2 n−5)(6−mn 2 )=6m 2 n−m 3 n 3 −30+5mn 2