Math, asked by kamakshiprabhu06, 5 months ago

find the product of each of the following 1) 7a²b⁶c⁴ and 9àma⁵bc⁸, 2) 3abc² and 2a²b , 3) (-3pt³) and (-6p²t²)..​

Answers

Answered by mapazeer
2

Step-by-step explanation:

P=(7a²b⁶c⁴)(9àma⁵bc⁸)= 63àma^7b^7c^12

P=(3abc²)(2a²b)= 6 a^3b^2c^2

P=(-3pt³) (-6p²t²)= 18 p^3 t^5

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