Math, asked by lohoward, 13 hours ago

Find the product of each pair of complex conjugates.(3 + 8i)(3 – 8i)

Answers

Answered by katcolucky
0

Answer:

Step-by-step explanation:

3*3=9

3 *-8i = -24i

8i *3 =24i

8i*-8i = -64i^2 or i^2 =-1. -64*-1=64

-24i + 24i =0

9+64= 73

Answer 73

Answered by sanskrutisakpal216
0

Step-by-step explanation:

By Difference of Squares,

a² – b² = (a + b)(a – b).

=> (3 + 8i)(3 – 8i) = 3² – (8i)²

= 9 – 64i² = 9 – 64(-1) = 73.

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