Find the product of each pair of complex conjugates.(3 + 8i)(3 – 8i)
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0
Answer:
Step-by-step explanation:
3*3=9
3 *-8i = -24i
8i *3 =24i
8i*-8i = -64i^2 or i^2 =-1. -64*-1=64
-24i + 24i =0
9+64= 73
Answer 73
Answered by
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Step-by-step explanation:
By Difference of Squares,
a² – b² = (a + b)(a – b).
=> (3 + 8i)(3 – 8i) = 3² – (8i)²
= 9 – 64i² = 9 – 64(-1) = 73.
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