Question

Find the product of
(i) (6a + 9b) and (3a + 2/5b + 4)​

Answer 1

Answer:

we have,

(6a+9b)×(3a+2/5b+4)

by using distrubutive property,

=6a×(3a+2/5b+4)+9b(3a+2/5b+4)

$= 18 {a}^{2} + \frac{12ab}{5} + 24a + 27ab + \frac{18 {b}^{2} }{5} + 36b$

$= 18 {a}^{2} + \frac{12ab}{5} +27ab + 24a + \frac{18 {b}^{2} }{5} + 36b$

$= 18 {a}^{2} + \frac{18 {b}^{2} }{5} + \frac{12ab + 135ab}{5} + 24a + 36b$

$= 18 {a}^{2} + \frac{18 {b}^{2} }{5} + \frac{147ab}{5} + 24a + 36b$